1/3+13/3x+40/3x^2

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Solution for 1/3+13/3x+40/3x^2 equation: 


x in (-oo:+oo)

(40/3)*x^2+(13/3)*x+1/3 = 0

40/3*x^2+13/3*x+1/3 = 0

DELTA = (13/3)^2-(1/3*4*40/3)

DELTA = 1

DELTA > 0

x = (1^(1/2)-13/3)/(2*40/3) or x = (-1^(1/2)-13/3)/(2*40/3)

x = -1/8 or x = -1/5

x in { -1/5, -1/8 }

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